105033304511341 has 4 divisors (see below), whose sum is σ = 105147595376800. Its totient is φ = 104919013645884.

The previous prime is 105033304511279. The next prime is 105033304511383. The reversal of 105033304511341 is 143115403330501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-105033304511341 is a prime.

It is a super-3 number, since 3×105033304511341³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 105033304511297 and 105033304511306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (105033304517341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57145431351 + ... + 57145433188.

It is an arithmetic number, because the mean of its divisors is an integer number (26286898844200).

Almost surely, 2^{105033304511341} is an apocalyptic number.

It is an amenable number.

105033304511341 is a deficient number, since it is larger than the sum of its proper divisors (114290865459).

105033304511341 is an equidigital number, since it uses as much as digits as its factorization.

105033304511341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114290865458.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 105033304511341 its reverse (143115403330501), we get a palindrome (248148707841842).

The spelling of 105033304511341 in words is "one hundred five trillion, thirty-three billion, three hundred four million, five hundred eleven thousand, three hundred forty-one".