Base | Representation |
---|---|
bin | 10011100100001110… |
… | …01011110001010001 |
3 | 1000010001220211212122 |
4 | 21302013023301101 |
5 | 133003112423213 |
6 | 4454202104025 |
7 | 521211046313 |
oct | 116207136121 |
9 | 30101824778 |
10 | 10504420433 |
11 | 4500520601 |
12 | 2051aab015 |
13 | cb535c5c0 |
14 | 7191497b3 |
15 | 4172ead08 |
hex | 2721cbc51 |
10504420433 has 8 divisors (see below), whose sum is σ = 11343282048. Its totient is φ = 9669963024.
The previous prime is 10504420403. The next prime is 10504420453. The reversal of 10504420433 is 33402440501.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10504420433 is a prime.
It is a super-2 number, since 2×105044204332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10504420403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1096091 + ... + 1105632.
It is an arithmetic number, because the mean of its divisors is an integer number (1417910256).
Almost surely, 210504420433 is an apocalyptic number.
10504420433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10504420433 is a deficient number, since it is larger than the sum of its proper divisors (838861615).
10504420433 is a wasteful number, since it uses less digits than its factorization.
10504420433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2202103.
The product of its (nonzero) digits is 5760, while the sum is 26.
Adding to 10504420433 its reverse (33402440501), we get a palindrome (43906860934).
The spelling of 10504420433 in words is "ten billion, five hundred four million, four hundred twenty thousand, four hundred thirty-three".
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