Base | Representation |
---|---|
bin | 11110100101001101101… |
… | …10110001011000100011 |
3 | 10201110020001202120122222 |
4 | 33102212312301120203 |
5 | 114203434434134011 |
6 | 2122415005421255 |
7 | 135626044333052 |
oct | 17224666613043 |
9 | 3643201676588 |
10 | 1050771396131 |
11 | 3756a2072306 |
12 | 14b79126a82b |
13 | 78119ab4a82 |
14 | 38c013b8399 |
15 | 1c4edbd2ddb |
hex | f4a6db1623 |
1050771396131 has 2 divisors, whose sum is σ = 1050771396132. Its totient is φ = 1050771396130.
The previous prime is 1050771396119. The next prime is 1050771396163. The reversal of 1050771396131 is 1316931770501.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (1316931770501) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1050771396131 is a prime.
It is a super-2 number, since 2×10507713961312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1050771396331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525385698065 + 525385698066.
It is an arithmetic number, because the mean of its divisors is an integer number (525385698066).
Almost surely, 21050771396131 is an apocalyptic number.
1050771396131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1050771396131 is an equidigital number, since it uses as much as digits as its factorization.
1050771396131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 119070, while the sum is 44.
The spelling of 1050771396131 in words is "one trillion, fifty billion, seven hundred seventy-one million, three hundred ninety-six thousand, one hundred thirty-one".
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