Base | Representation |
---|---|
bin | 110000111100101000… |
… | …0110000100111000011 |
3 | 101001022112212202120022 |
4 | 1201321100300213003 |
5 | 3210233043323101 |
6 | 120142154204055 |
7 | 10410546203621 |
oct | 1417120604703 |
9 | 331275782508 |
10 | 105113651651 |
11 | 4063aa09298 |
12 | 1845642362b |
13 | 9bb2081818 |
14 | 5132268511 |
15 | 2b03140a1b |
hex | 18794309c3 |
105113651651 has 2 divisors, whose sum is σ = 105113651652. Its totient is φ = 105113651650.
The previous prime is 105113651647. The next prime is 105113651653. The reversal of 105113651651 is 156156311501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 105113651651 - 22 = 105113651647 is a prime.
It is a super-2 number, since 2×1051136516512 (a number of 23 digits) contains 22 as substring.
Together with 105113651653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (105113651653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52556825825 + 52556825826.
It is an arithmetic number, because the mean of its divisors is an integer number (52556825826).
Almost surely, 2105113651651 is an apocalyptic number.
105113651651 is a deficient number, since it is larger than the sum of its proper divisors (1).
105113651651 is an equidigital number, since it uses as much as digits as its factorization.
105113651651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 35.
The spelling of 105113651651 in words is "one hundred five billion, one hundred thirteen million, six hundred fifty-one thousand, six hundred fifty-one".
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