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1051212255113 is a prime number
BaseRepresentation
bin11110100110000010010…
…00100000111110001001
310201111100210022112111102
433103001020200332021
5114210340314130423
62122530434511145
7135643006511156
oct17230110407611
93644323275442
101051212255113
113758a8a05179
1214b894a354b5
137818a230b87
1438c43b7722d
151c527767c28
hexf4c1220f89

1051212255113 has 2 divisors, whose sum is σ = 1051212255114. Its totient is φ = 1051212255112.

The previous prime is 1051212255109. The next prime is 1051212255127. The reversal of 1051212255113 is 3115522121501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 997447630729 + 53764624384 = 998723^2 + 231872^2 .

It is a cyclic number.

It is not a de Polignac number, because 1051212255113 - 22 = 1051212255109 is a prime.

It is a super-2 number, since 2×10512122551132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1051212251113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525606127556 + 525606127557.

It is an arithmetic number, because the mean of its divisors is an integer number (525606127557).

Almost surely, 21051212255113 is an apocalyptic number.

It is an amenable number.

1051212255113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1051212255113 is an equidigital number, since it uses as much as digits as its factorization.

1051212255113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3000, while the sum is 29.

Adding to 1051212255113 its reverse (3115522121501), we get a palindrome (4166734376614).

The spelling of 1051212255113 in words is "one trillion, fifty-one billion, two hundred twelve million, two hundred fifty-five thousand, one hundred thirteen".