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105121451 is a prime number
BaseRepresentation
bin1100100010000…
…00011010101011
321022210201112002
412101000122223
5203402341301
614233041215
72414342351
oct621003253
9238721462
10105121451
115437a336
122b25620b
1318a17956
14dd657d1
15936716b
hex64406ab

105121451 has 2 divisors, whose sum is σ = 105121452. Its totient is φ = 105121450.

The previous prime is 105121447. The next prime is 105121463. The reversal of 105121451 is 154121501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 105121451 - 22 = 105121447 is a prime.

It is a super-2 number, since 2×1051214512 = 22101038920690802, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (105121411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52560725 + 52560726.

It is an arithmetic number, because the mean of its divisors is an integer number (52560726).

Almost surely, 2105121451 is an apocalyptic number.

105121451 is a deficient number, since it is larger than the sum of its proper divisors (1).

105121451 is an equidigital number, since it uses as much as digits as its factorization.

105121451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 200, while the sum is 20.

The square root of 105121451 is about 10252.8752552638. The cubic root of 105121451 is about 471.9512227556.

Adding to 105121451 its reverse (154121501), we get a palindrome (259242952).

Subtracting 105121451 from its reverse (154121501), we obtain a triangular number (49000050 = T9899).

The spelling of 105121451 in words is "one hundred five million, one hundred twenty-one thousand, four hundred fifty-one".