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105122401956743 is a prime number
BaseRepresentation
bin10111111001101110110111…
…011011010011001110000111
3111210012121021221022022102012
4113321232313123103032013
5102234311134400103433
61011324321554004435
731066562055313223
oct2771566733231607
9453177257268365
10105122401956743
113054a184407476
12b95951387671b
134686cccc16a42
141bd5d4690d783
15c2471cca7848
hex5f9bb76d3387

105122401956743 has 2 divisors, whose sum is σ = 105122401956744. Its totient is φ = 105122401956742.

The previous prime is 105122401956731. The next prime is 105122401956749. The reversal of 105122401956743 is 347659104221501.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 105122401956743 - 224 = 105122385179527 is a prime.

It is a super-2 number, since 2×1051224019567432 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105122401956691 and 105122401956700.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105122401956749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52561200978371 + 52561200978372.

It is an arithmetic number, because the mean of its divisors is an integer number (52561200978372).

Almost surely, 2105122401956743 is an apocalyptic number.

105122401956743 is a deficient number, since it is larger than the sum of its proper divisors (1).

105122401956743 is an equidigital number, since it uses as much as digits as its factorization.

105122401956743 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1814400, while the sum is 50.

The spelling of 105122401956743 in words is "one hundred five trillion, one hundred twenty-two billion, four hundred one million, nine hundred fifty-six thousand, seven hundred forty-three".