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1051232241013 is a prime number
BaseRepresentation
bin11110100110000100101…
…00110000010101110101
310201111102011220220222221
433103002110300111311
5114210410423203023
62122532431122341
7135643341421123
oct17230224602565
93644364826887
101051232241013
11375909215949
1214b89b6733b1
137819140aa56
1438c4669a913
151c5293b485d
hexf4c2530575

1051232241013 has 2 divisors, whose sum is σ = 1051232241014. Its totient is φ = 1051232241012.

The previous prime is 1051232240941. The next prime is 1051232241023. The reversal of 1051232241013 is 3101422321501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 927288109764 + 123944131249 = 962958^2 + 352057^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1051232241013 is a prime.

It is a super-2 number, since 2×10512322410132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1051232241023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525616120506 + 525616120507.

It is an arithmetic number, because the mean of its divisors is an integer number (525616120507).

Almost surely, 21051232241013 is an apocalyptic number.

It is an amenable number.

1051232241013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1051232241013 is an equidigital number, since it uses as much as digits as its factorization.

1051232241013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1051232241013 its reverse (3101422321501), we get a palindrome (4152654562514).

The spelling of 1051232241013 in words is "one trillion, fifty-one billion, two hundred thirty-two million, two hundred forty-one thousand, thirteen".