Base | Representation |
---|---|
bin | 11110100110010010011… |
… | …11101011010001000111 |
3 | 10201111201021101212121122 |
4 | 33103021033223101013 |
5 | 114211130134200043 |
6 | 2122552135504155 |
7 | 135646251345266 |
oct | 17231117532107 |
9 | 3644637355548 |
10 | 1051348350023 |
11 | 37596880a304 |
12 | 14b91252805b |
13 | 781ac4a18ca |
14 | 38c57c825dd |
15 | 1c53469c368 |
hex | f4c93eb447 |
1051348350023 has 2 divisors, whose sum is σ = 1051348350024. Its totient is φ = 1051348350022.
The previous prime is 1051348350011. The next prime is 1051348350037. The reversal of 1051348350023 is 3200538431501.
It is a weak prime.
It is an emirp because it is prime and its reverse (3200538431501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1051348350023 - 24 = 1051348350007 is a prime.
It is a super-2 number, since 2×10513483500232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1051348353023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525674175011 + 525674175012.
It is an arithmetic number, because the mean of its divisors is an integer number (525674175012).
Almost surely, 21051348350023 is an apocalyptic number.
1051348350023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1051348350023 is an equidigital number, since it uses as much as digits as its factorization.
1051348350023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 35.
The spelling of 1051348350023 in words is "one trillion, fifty-one billion, three hundred forty-eight million, three hundred fifty thousand, twenty-three".
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