Base | Representation |
---|---|
bin | 11110100110101010100… |
… | …01010110010111101011 |
3 | 10201112020100001121112221 |
4 | 33103111101112113223 |
5 | 114212033312142212 |
6 | 2123024144214511 |
7 | 135654251334256 |
oct | 17232521262753 |
9 | 3645210047487 |
10 | 1051550115307 |
11 | 375a6169857a |
12 | 14b96a00a437 |
13 | 78212226553 |
14 | 38c769a409d |
15 | 1c547254807 |
hex | f4d54565eb |
1051550115307 has 2 divisors, whose sum is σ = 1051550115308. Its totient is φ = 1051550115306.
The previous prime is 1051550115293. The next prime is 1051550115337. The reversal of 1051550115307 is 7035110551501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1051550115307 - 223 = 1051541726699 is a prime.
It is a super-2 number, since 2×10515501153072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1051550115337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525775057653 + 525775057654.
It is an arithmetic number, because the mean of its divisors is an integer number (525775057654).
Almost surely, 21051550115307 is an apocalyptic number.
1051550115307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1051550115307 is an equidigital number, since it uses as much as digits as its factorization.
1051550115307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13125, while the sum is 34.
Adding to 1051550115307 its reverse (7035110551501), we get a palindrome (8086660666808).
The spelling of 1051550115307 in words is "one trillion, fifty-one billion, five hundred fifty million, one hundred fifteen thousand, three hundred seven".
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