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105201443021261 is a prime number
BaseRepresentation
bin10111111010111000011110…
…101001000010000111001101
3111210111011022110000102020012
4113322320132221002013031
5102242110023403140021
61011424513054203005
731105360554264446
oct2772703651020715
9453434273012205
10105201443021261
113057a754a98094
12b9708b24b3465
1346915b848b8c2
141bd9ac418a2cd
15c267e6ea735b
hex5fae1ea421cd

105201443021261 has 2 divisors, whose sum is σ = 105201443021262. Its totient is φ = 105201443021260.

The previous prime is 105201443021201. The next prime is 105201443021267. The reversal of 105201443021261 is 162120344102501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54494012584036 + 50707430437225 = 7382006^2 + 7120915^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-105201443021261 is a prime.

It is a super-2 number, since 2×1052014430212612 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105201443021267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52600721510630 + 52600721510631.

It is an arithmetic number, because the mean of its divisors is an integer number (52600721510631).

Almost surely, 2105201443021261 is an apocalyptic number.

It is an amenable number.

105201443021261 is a deficient number, since it is larger than the sum of its proper divisors (1).

105201443021261 is an equidigital number, since it uses as much as digits as its factorization.

105201443021261 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 105201443021261 its reverse (162120344102501), we get a palindrome (267321787123762).

The spelling of 105201443021261 in words is "one hundred five trillion, two hundred one billion, four hundred forty-three million, twenty-one thousand, two hundred sixty-one".