Base | Representation |
---|---|
bin | 1001100100011000000100… |
… | …1100000100000110100111 |
3 | 1101020202100200110112000012 |
4 | 2121012001030010012213 |
5 | 2334332032314100203 |
6 | 34213023113440435 |
7 | 2134040563222454 |
oct | 231060114040647 |
9 | 41222320415005 |
10 | 10520542331303 |
11 | 3396811970024 |
12 | 121ab5041011b |
13 | 5b4110137a04 |
14 | 2852a868c82b |
15 | 1339e421cbd8 |
hex | 991813041a7 |
10520542331303 has 2 divisors, whose sum is σ = 10520542331304. Its totient is φ = 10520542331302.
The previous prime is 10520542331281. The next prime is 10520542331363. The reversal of 10520542331303 is 30313324502501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10520542331303 - 224 = 10520525554087 is a prime.
It is a super-2 number, since 2×105205423313032 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 10520542331303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10520542331363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5260271165651 + 5260271165652.
It is an arithmetic number, because the mean of its divisors is an integer number (5260271165652).
Almost surely, 210520542331303 is an apocalyptic number.
10520542331303 is a deficient number, since it is larger than the sum of its proper divisors (1).
10520542331303 is an equidigital number, since it uses as much as digits as its factorization.
10520542331303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 10520542331303 its reverse (30313324502501), we get a palindrome (40833866833804).
The spelling of 10520542331303 in words is "ten trillion, five hundred twenty billion, five hundred forty-two million, three hundred thirty-one thousand, three hundred three".
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