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105211053331 is a prime number
BaseRepresentation
bin110000111111100010…
…0010100010100010011
3101001120100011021112221
41201333010110110103
53210433012201311
6120155554001511
710413141124546
oct1417704242423
9331510137487
10105211053331
114068a99564a
1218482b76297
139bc92c5757
14514118085d
152b0b980671
hex187f114513

105211053331 has 2 divisors, whose sum is σ = 105211053332. Its totient is φ = 105211053330.

The previous prime is 105211053317. The next prime is 105211053379. The reversal of 105211053331 is 133350112501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 105211053331 - 27 = 105211053203 is a prime.

It is a super-2 number, since 2×1052110533312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105211053296 and 105211053305.

It is not a weakly prime, because it can be changed into another prime (105211023331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52605526665 + 52605526666.

It is an arithmetic number, because the mean of its divisors is an integer number (52605526666).

Almost surely, 2105211053331 is an apocalyptic number.

105211053331 is a deficient number, since it is larger than the sum of its proper divisors (1).

105211053331 is an equidigital number, since it uses as much as digits as its factorization.

105211053331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 105211053331 its reverse (133350112501), we get a palindrome (238561165832).

The spelling of 105211053331 in words is "one hundred five billion, two hundred eleven million, fifty-three thousand, three hundred thirty-one".