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1052174009693 = 4348724195139
BaseRepresentation
bin11110100111110100111…
…01010100010101011101
310201120211211000201202102
433103322131110111131
5114214323021302233
62123210112334445
7136005565342322
oct17237235242535
93646754021672
101052174009693
11376251886674
1214bb02b44425
13782b156a021
1438cd57aab49
151c581de21e8
hexf4fa75455d

1052174009693 has 4 divisors (see below), whose sum is σ = 1052198248320. Its totient is φ = 1052149771068.

The previous prime is 1052174009681. The next prime is 1052174009713. The reversal of 1052174009693 is 3969004712501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1052174009693 - 214 = 1052173993309 is a prime.

It is a super-2 number, since 2×10521740096932 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1052174009893) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12054083 + ... + 12141056.

It is an arithmetic number, because the mean of its divisors is an integer number (263049562080).

Almost surely, 21052174009693 is an apocalyptic number.

It is an amenable number.

1052174009693 is a deficient number, since it is larger than the sum of its proper divisors (24238627).

1052174009693 is an equidigital number, since it uses as much as digits as its factorization.

1052174009693 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24238626.

The product of its (nonzero) digits is 408240, while the sum is 47.

The spelling of 1052174009693 in words is "one trillion, fifty-two billion, one hundred seventy-four million, nine thousand, six hundred ninety-three".

Divisors: 1 43487 24195139 1052174009693