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10525476133 is a prime number
BaseRepresentation
bin10011100110101111…
…00000010100100101
31000011112112120212101
421303113200110211
5133024010214013
64500233252101
7521555033224
oct116327402445
930145476771
1010525476133
1145113a2007
122058b64031
13cb98223b3
1471bc6acbb
154190a98dd
hex2735e0525

10525476133 has 2 divisors, whose sum is σ = 10525476134. Its totient is φ = 10525476132.

The previous prime is 10525476083. The next prime is 10525476139. The reversal of 10525476133 is 33167452501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9723340449 + 802135684 = 98607^2 + 28322^2 .

It is an emirp because it is prime and its reverse (33167452501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10525476133 is a prime.

It is a super-2 number, since 2×105254761332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10525476092 and 10525476101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10525476139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5262738066 + 5262738067.

It is an arithmetic number, because the mean of its divisors is an integer number (5262738067).

Almost surely, 210525476133 is an apocalyptic number.

It is an amenable number.

10525476133 is a deficient number, since it is larger than the sum of its proper divisors (1).

10525476133 is an equidigital number, since it uses as much as digits as its factorization.

10525476133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75600, while the sum is 37.

The spelling of 10525476133 in words is "ten billion, five hundred twenty-five million, four hundred seventy-six thousand, one hundred thirty-three".