105311301130221 has 4 divisors (see below), whose sum is σ = 140415068173632. Its totient is φ = 70207534086812.

The previous prime is 105311301130201. The next prime is 105311301130229. The reversal of 105311301130221 is 122031103113501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 105311301130221 - 2²⁷ = 105311166912493 is a prime.

It is a super-2 number, since 2×105311301130221² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105311301130191 and 105311301130200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (105311301130229) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17551883521701 + ... + 17551883521706.

It is an arithmetic number, because the mean of its divisors is an integer number (35103767043408).

Almost surely, 2^{105311301130221} is an apocalyptic number.

It is an amenable number.

105311301130221 is a deficient number, since it is larger than the sum of its proper divisors (35103767043411).

105311301130221 is an equidigital number, since it uses as much as digits as its factorization.

105311301130221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35103767043410.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 105311301130221 its reverse (122031103113501), we get a palindrome (227342404243722).

The spelling of 105311301130221 in words is "one hundred five trillion, three hundred eleven billion, three hundred one million, one hundred thirty thousand, two hundred twenty-one".