1053131413 has 2 divisors, whose sum is σ = 1053131414. Its totient is φ = 1053131412.

The previous prime is 1053131399. The next prime is 1053131437. The reversal of 1053131413 is 3141313501.

1053131413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1040578564 + 12552849 = 32258^2 + 3543^2 .

It is an emirp because it is prime and its reverse (3141313501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1053131413 is a prime.

It is a super-2 number, since 2×1053131413² = 2218171546094753138, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1053131483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526565706 + 526565707.

It is an arithmetic number, because the mean of its divisors is an integer number (526565707).

Almost surely, 2^1053131413 is an apocalyptic number.

It is an amenable number.

1053131413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053131413 is an equidigital number, since it uses as much as digits as its factorization.

1053131413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 1053131413 is about 32451.9862720296. The cubic root of 1053131413 is about 1017.4057530117.

Adding to 1053131413 its reverse (3141313501), we get a palindrome (4194444914).

The spelling of 1053131413 in words is "one billion, fifty-three million, one hundred thirty-one thousand, four hundred thirteen".