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105313555010131 = 138101042693087
BaseRepresentation
bin10111111100100000111001…
…000010010101001001010011
3111210212212200201111112200021
4113330200321002111021103
5102300424130040311011
61011552213531204311
731116440032414036
oct2774407102251123
9453785621445607
10105313555010131
1130613256314746
12b98a5805a6697
13469c0443b3560
141c012bba5b01d
15c296a96d4471
hex5fc839095253

105313555010131 has 4 divisors (see below), whose sum is σ = 113414597703232. Its totient is φ = 97212512317032.

The previous prime is 105313555010107. The next prime is 105313555010161. The reversal of 105313555010131 is 131010555313501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 105313555010131 - 25 = 105313555010099 is a prime.

It is a super-2 number, since 2×1053135550101312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105313555010161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4050521346531 + ... + 4050521346556.

It is an arithmetic number, because the mean of its divisors is an integer number (28353649425808).

Almost surely, 2105313555010131 is an apocalyptic number.

105313555010131 is a deficient number, since it is larger than the sum of its proper divisors (8101042693101).

105313555010131 is an equidigital number, since it uses as much as digits as its factorization.

105313555010131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8101042693100.

The product of its (nonzero) digits is 16875, while the sum is 34.

The spelling of 105313555010131 in words is "one hundred five trillion, three hundred thirteen billion, five hundred fifty-five million, ten thousand, one hundred thirty-one".

Divisors: 1 13 8101042693087 105313555010131