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105314147 is a prime number
BaseRepresentation
bin1100100011011…
…11011101100011
321100011111211222
412101233131203
5203430023042
614241125255
72416104221
oct621573543
9240144758
10105314147
11544a1094
122b32982b
1318a84583
14ddb5b11
1593a42d2
hex646f763

105314147 has 2 divisors, whose sum is σ = 105314148. Its totient is φ = 105314146.

The previous prime is 105314129. The next prime is 105314149. The reversal of 105314147 is 741413501.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 105314147 - 220 = 104265571 is a prime.

It is a super-2 number, since 2×1053141472 = 22182139116675218, which contains 22 as substring.

Together with 105314149, it forms a pair of twin primes.

It is a Chen prime.

It is equal to p6049700 and since 105314147 and 6049700 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (105314149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52657073 + 52657074.

It is an arithmetic number, because the mean of its divisors is an integer number (52657074).

Almost surely, 2105314147 is an apocalyptic number.

105314147 is a deficient number, since it is larger than the sum of its proper divisors (1).

105314147 is an equidigital number, since it uses as much as digits as its factorization.

105314147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 26.

The square root of 105314147 is about 10262.2681216191. The cubic root of 105314147 is about 472.2394214687.

Adding to 105314147 its reverse (741413501), we get a palindrome (846727648).

The spelling of 105314147 in words is "one hundred five million, three hundred fourteen thousand, one hundred forty-seven".