Base | Representation |
---|---|
bin | 11110101001110100010… |
… | …00101110101100100111 |
3 | 10201200121021022021021112 |
4 | 33110322020232230213 |
5 | 114224020020320341 |
6 | 2123504114535235 |
7 | 136044220204166 |
oct | 17247210565447 |
9 | 3650537267245 |
10 | 1053242354471 |
11 | 37674a93a93a |
12 | 15016089751b |
13 | 784219b64b8 |
14 | 38d976293dd |
15 | 1c5e5ac3aeb |
hex | f53a22eb27 |
1053242354471 has 2 divisors, whose sum is σ = 1053242354472. Its totient is φ = 1053242354470.
The previous prime is 1053242354467. The next prime is 1053242354477. The reversal of 1053242354471 is 1744532423501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1053242354471 - 22 = 1053242354467 is a prime.
It is a super-3 number, since 3×10532423544713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1053242354477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526621177235 + 526621177236.
It is an arithmetic number, because the mean of its divisors is an integer number (526621177236).
Almost surely, 21053242354471 is an apocalyptic number.
1053242354471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1053242354471 is an equidigital number, since it uses as much as digits as its factorization.
1053242354471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 41.
Adding to 1053242354471 its reverse (1744532423501), we get a palindrome (2797774777972).
The spelling of 1053242354471 in words is "one trillion, fifty-three billion, two hundred forty-two million, three hundred fifty-four thousand, four hundred seventy-one".
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