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1053242354471 is a prime number
BaseRepresentation
bin11110101001110100010…
…00101110101100100111
310201200121021022021021112
433110322020232230213
5114224020020320341
62123504114535235
7136044220204166
oct17247210565447
93650537267245
101053242354471
1137674a93a93a
1215016089751b
13784219b64b8
1438d976293dd
151c5e5ac3aeb
hexf53a22eb27

1053242354471 has 2 divisors, whose sum is σ = 1053242354472. Its totient is φ = 1053242354470.

The previous prime is 1053242354467. The next prime is 1053242354477. The reversal of 1053242354471 is 1744532423501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1053242354471 - 22 = 1053242354467 is a prime.

It is a super-3 number, since 3×10532423544713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1053242354477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526621177235 + 526621177236.

It is an arithmetic number, because the mean of its divisors is an integer number (526621177236).

Almost surely, 21053242354471 is an apocalyptic number.

1053242354471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053242354471 is an equidigital number, since it uses as much as digits as its factorization.

1053242354471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 403200, while the sum is 41.

Adding to 1053242354471 its reverse (1744532423501), we get a palindrome (2797774777972).

The spelling of 1053242354471 in words is "one trillion, fifty-three billion, two hundred forty-two million, three hundred fifty-four thousand, four hundred seventy-one".