1053311123983 has 4 divisors (see below), whose sum is σ = 1087288902208. Its totient is φ = 1019333345760.

The previous prime is 1053311123981. The next prime is 1053311123993. The reversal of 1053311123983 is 3893211133501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1053311123983 - 2¹ = 1053311123981 is a prime.

It is a super-3 number, since 3×1053311123983³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1053311123981) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16988889066 + ... + 16988889127.

It is an arithmetic number, because the mean of its divisors is an integer number (271822225552).

Almost surely, 2^{1053311123983} is an apocalyptic number.

1053311123983 is a deficient number, since it is larger than the sum of its proper divisors (33977778225).

1053311123983 is an equidigital number, since it uses as much as digits as its factorization.

1053311123983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33977778224.

The product of its (nonzero) digits is 58320, while the sum is 40.

The spelling of 1053311123983 in words is "one trillion, fifty-three billion, three hundred eleven million, one hundred twenty-three thousand, nine hundred eighty-three".