Base | Representation |
---|---|
bin | 11110101010000010100… |
… | …01101001010111000111 |
3 | 10201200220121200121201222 |
4 | 33111001101221113013 |
5 | 114224241201214143 |
6 | 2123524034110555 |
7 | 136050203252066 |
oct | 17250121512707 |
9 | 3650817617658 |
10 | 1053362132423 |
11 | 37680150a887 |
12 | 150194a1b45b |
13 | 78440763323 |
14 | 38da94c81dd |
15 | 1c601383768 |
hex | f5414695c7 |
1053362132423 has 2 divisors, whose sum is σ = 1053362132424. Its totient is φ = 1053362132422.
The previous prime is 1053362132399. The next prime is 1053362132429. The reversal of 1053362132423 is 3242312633501.
1053362132423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1053362132423 - 28 = 1053362132167 is a prime.
It is a super-2 number, since 2×10533621324232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1053362132429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526681066211 + 526681066212.
It is an arithmetic number, because the mean of its divisors is an integer number (526681066212).
Almost surely, 21053362132423 is an apocalyptic number.
1053362132423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1053362132423 is an equidigital number, since it uses as much as digits as its factorization.
1053362132423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 1053362132423 its reverse (3242312633501), we get a palindrome (4295674765924).
The spelling of 1053362132423 in words is "one trillion, fifty-three billion, three hundred sixty-two million, one hundred thirty-two thousand, four hundred twenty-three".
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