Base | Representation |
---|---|
bin | 11110101010001001100… |
… | …00000101011000001111 |
3 | 10201201001200102010000120 |
4 | 33111010300011120033 |
5 | 114224401113140101 |
6 | 2123533520000023 |
7 | 136051512012156 |
oct | 17250460053017 |
9 | 3651050363016 |
10 | 1053420443151 |
11 | 37683141756a |
12 | 1501b0460013 |
13 | 7844c86b40b |
14 | 38db314659d |
15 | 1c606550b36 |
hex | f544c0560f |
1053420443151 has 8 divisors (see below), whose sum is σ = 1404566863920. Its totient is φ = 702277158912.
The previous prime is 1053420443029. The next prime is 1053420443233. The reversal of 1053420443151 is 1513440243501.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1053420443151 - 213 = 1053420434959 is a prime.
It is a super-2 number, since 2×10534204431512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1053420423151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 162945 + ... + 1460613.
It is an arithmetic number, because the mean of its divisors is an integer number (175570857990).
Almost surely, 21053420443151 is an apocalyptic number.
1053420443151 is a deficient number, since it is larger than the sum of its proper divisors (351146420769).
1053420443151 is a wasteful number, since it uses less digits than its factorization.
1053420443151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1568265.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 1053420443151 its reverse (1513440243501), we get a palindrome (2566860686652).
The spelling of 1053420443151 in words is "one trillion, fifty-three billion, four hundred twenty million, four hundred forty-three thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •