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1053420443151 = 32705931297669
BaseRepresentation
bin11110101010001001100…
…00000101011000001111
310201201001200102010000120
433111010300011120033
5114224401113140101
62123533520000023
7136051512012156
oct17250460053017
93651050363016
101053420443151
1137683141756a
121501b0460013
137844c86b40b
1438db314659d
151c606550b36
hexf544c0560f

1053420443151 has 8 divisors (see below), whose sum is σ = 1404566863920. Its totient is φ = 702277158912.

The previous prime is 1053420443029. The next prime is 1053420443233. The reversal of 1053420443151 is 1513440243501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1053420443151 - 213 = 1053420434959 is a prime.

It is a super-2 number, since 2×10534204431512 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1053420423151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 162945 + ... + 1460613.

It is an arithmetic number, because the mean of its divisors is an integer number (175570857990).

Almost surely, 21053420443151 is an apocalyptic number.

1053420443151 is a deficient number, since it is larger than the sum of its proper divisors (351146420769).

1053420443151 is a wasteful number, since it uses less digits than its factorization.

1053420443151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1568265.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 1053420443151 its reverse (1513440243501), we get a palindrome (2566860686652).

The spelling of 1053420443151 in words is "one trillion, fifty-three billion, four hundred twenty million, four hundred forty-three thousand, one hundred fifty-one".

Divisors: 1 3 270593 811779 1297669 3893007 351140147717 1053420443151