Base | Representation |
---|---|
bin | 110001000011011110… |
… | …1001110011110110101 |
3 | 101001220120012210201101 |
4 | 1202012331032132311 |
5 | 3211220403142044 |
6 | 120221042530101 |
7 | 10416336141403 |
oct | 1420675163665 |
9 | 331816183641 |
10 | 105343412149 |
11 | 407486787a8 |
12 | 184bb366931 |
13 | 9c1a858a91 |
14 | 5154996473 |
15 | 2b183c7cd4 |
hex | 1886f4e7b5 |
105343412149 has 2 divisors, whose sum is σ = 105343412150. Its totient is φ = 105343412148.
The previous prime is 105343412123. The next prime is 105343412159. The reversal of 105343412149 is 941214343501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105303495025 + 39917124 = 324505^2 + 6318^2 .
It is a cyclic number.
It is not a de Polignac number, because 105343412149 - 217 = 105343281077 is a prime.
It is a super-2 number, since 2×1053434121492 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105343412159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52671706074 + 52671706075.
It is an arithmetic number, because the mean of its divisors is an integer number (52671706075).
Almost surely, 2105343412149 is an apocalyptic number.
It is an amenable number.
105343412149 is a deficient number, since it is larger than the sum of its proper divisors (1).
105343412149 is an equidigital number, since it uses as much as digits as its factorization.
105343412149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 105343412149 in words is "one hundred five billion, three hundred forty-three million, four hundred twelve thousand, one hundred forty-nine".
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