Base | Representation |
---|---|
bin | 110001000011011110… |
… | …1001110011111001101 |
3 | 101001220120012210202021 |
4 | 1202012331032133031 |
5 | 3211220403142143 |
6 | 120221042530141 |
7 | 10416336141436 |
oct | 1420675163715 |
9 | 331816183667 |
10 | 105343412173 |
11 | 4074867881a |
12 | 184bb366951 |
13 | 9c1a858aac |
14 | 515499648d |
15 | 2b183c7ced |
hex | 1886f4e7cd |
105343412173 has 2 divisors, whose sum is σ = 105343412174. Its totient is φ = 105343412172.
The previous prime is 105343412159. The next prime is 105343412189. The reversal of 105343412173 is 371214343501.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52926683364 + 52416728809 = 230058^2 + 228947^2 .
It is a cyclic number.
It is not a de Polignac number, because 105343412173 - 213 = 105343403981 is a prime.
It is a super-2 number, since 2×1053434121732 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105343412123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52671706086 + 52671706087.
It is an arithmetic number, because the mean of its divisors is an integer number (52671706087).
Almost surely, 2105343412173 is an apocalyptic number.
It is an amenable number.
105343412173 is a deficient number, since it is larger than the sum of its proper divisors (1).
105343412173 is an equidigital number, since it uses as much as digits as its factorization.
105343412173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30240, while the sum is 34.
Adding to 105343412173 its reverse (371214343501), we get a palindrome (476557755674).
The spelling of 105343412173 in words is "one hundred five billion, three hundred forty-three million, four hundred twelve thousand, one hundred seventy-three".
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