Base | Representation |
---|---|
bin | 11110101010010000111… |
… | …00001111010010011111 |
3 | 10201201012222220021212201 |
4 | 33111020130033102133 |
5 | 114230012440142402 |
6 | 2123544010512331 |
7 | 136053163136623 |
oct | 17251034172237 |
9 | 3651188807781 |
10 | 1053482349727 |
11 | 37686335a925 |
12 | 1502091356a7 |
13 | 7845c635122 |
14 | 38dbb45d183 |
15 | 1c60bbcd687 |
hex | f54870f49f |
1053482349727 has 2 divisors, whose sum is σ = 1053482349728. Its totient is φ = 1053482349726.
The previous prime is 1053482349719. The next prime is 1053482349767. The reversal of 1053482349727 is 7279432843501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1053482349727 - 23 = 1053482349719 is a prime.
It is a super-3 number, since 3×10534823497273 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1053482349767) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526741174863 + 526741174864.
It is an arithmetic number, because the mean of its divisors is an integer number (526741174864).
Almost surely, 21053482349727 is an apocalyptic number.
1053482349727 is a deficient number, since it is larger than the sum of its proper divisors (1).
1053482349727 is an equidigital number, since it uses as much as digits as its factorization.
1053482349727 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10160640, while the sum is 55.
The spelling of 1053482349727 in words is "one trillion, fifty-three billion, four hundred eighty-two million, three hundred forty-nine thousand, seven hundred twenty-seven".
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