10536433 has 2 divisors, whose sum is σ = 10536434. Its totient is φ = 10536432.

The previous prime is 10536403. The next prime is 10536437. The reversal of 10536433 is 33463501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6012304 + 4524129 = 2452^2 + 2127^2 .

It is a cyclic number.

It is not a de Polignac number, because 10536433 - 2²¹ = 8439281 is a prime.

It is a super-2 number, since 2×10536433² = 222032840726978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10536398 and 10536407.

It is not a weakly prime, because it can be changed into another prime (10536437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5268216 + 5268217.

It is an arithmetic number, because the mean of its divisors is an integer number (5268217).

Almost surely, 2^10536433 is an apocalyptic number.

It is an amenable number.

10536433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10536433 is an equidigital number, since it uses as much as digits as its factorization.

10536433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 10536433 is about 3245.9872150087. The cubic root of 10536433 is about 219.2289329139.

Adding to 10536433 its reverse (33463501), we get a palindrome (43999934).

The spelling of 10536433 in words is "ten million, five hundred thirty-six thousand, four hundred thirty-three".