Base | Representation |
---|---|
bin | 110001000101100010… |
… | …0111001011110101111 |
3 | 101002002101021110112011 |
4 | 1202023010321132233 |
5 | 3211341102012033 |
6 | 120231552222051 |
7 | 10421135511412 |
oct | 1421304713657 |
9 | 332071243464 |
10 | 105412532143 |
11 | 40783698666 |
12 | 1851a53a927 |
13 | 9c2bc79b99 |
14 | 515dc29b79 |
15 | 2b1e4ccccd |
hex | 188b1397af |
105412532143 has 2 divisors, whose sum is σ = 105412532144. Its totient is φ = 105412532142.
The previous prime is 105412532131. The next prime is 105412532161. The reversal of 105412532143 is 341235214501.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-105412532143 is a prime.
It is a super-2 number, since 2×1054125321432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105412532443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52706266071 + 52706266072.
It is an arithmetic number, because the mean of its divisors is an integer number (52706266072).
Almost surely, 2105412532143 is an apocalyptic number.
105412532143 is a deficient number, since it is larger than the sum of its proper divisors (1).
105412532143 is an equidigital number, since it uses as much as digits as its factorization.
105412532143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 105412532143 its reverse (341235214501), we get a palindrome (446647746644).
The spelling of 105412532143 in words is "one hundred five billion, four hundred twelve million, five hundred thirty-two thousand, one hundred forty-three".
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