1054144331401 has 4 divisors (see below), whose sum is σ = 1204736378752. Its totient is φ = 903552284052.

The previous prime is 1054144331369. The next prime is 1054144331413. The reversal of 1054144331401 is 1041334414501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1054144331401 - 2⁵ = 1054144331369 is a prime.

It is a super-2 number, since 2×1054144331401² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1054144331431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75296023665 + ... + 75296023678.

It is an arithmetic number, because the mean of its divisors is an integer number (301184094688).

Almost surely, 2^{1054144331401} is an apocalyptic number.

It is an amenable number.

1054144331401 is a deficient number, since it is larger than the sum of its proper divisors (150592047351).

1054144331401 is an equidigital number, since it uses as much as digits as its factorization.

1054144331401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150592047350.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1054144331401 its reverse (1041334414501), we get a palindrome (2095478745902).

The spelling of 1054144331401 in words is "one trillion, fifty-four billion, one hundred forty-four million, three hundred thirty-one thousand, four hundred one".