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1054144331413 is a prime number
BaseRepresentation
bin11110101011011111110…
…01011111111010010101
310201202221010112110000221
433111233321133322111
5114232341422101123
62124133415234341
7136105451655445
oct17255771377225
93652833473027
101054144331413
11377072aa2528
121503729789b1
1378536822974
143904133c125
151c649d9125d
hexf56fe5fe95

1054144331413 has 2 divisors, whose sum is σ = 1054144331414. Its totient is φ = 1054144331412.

The previous prime is 1054144331369. The next prime is 1054144331417. The reversal of 1054144331413 is 3141334414501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1003727467044 + 50416864369 = 1001862^2 + 224537^2 .

It is an emirp because it is prime and its reverse (3141334414501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1054144331413 is a prime.

It is a super-2 number, since 2×10541443314132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1054144331417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527072165706 + 527072165707.

It is an arithmetic number, because the mean of its divisors is an integer number (527072165707).

Almost surely, 21054144331413 is an apocalyptic number.

It is an amenable number.

1054144331413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1054144331413 is an equidigital number, since it uses as much as digits as its factorization.

1054144331413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 1054144331413 its reverse (3141334414501), we get a palindrome (4195478745914).

The spelling of 1054144331413 in words is "one trillion, fifty-four billion, one hundred forty-four million, three hundred thirty-one thousand, four hundred thirteen".