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10542131101 is a prime number
BaseRepresentation
bin10011101000101110…
…00010011110011101
31000012200212202012001
421310113002132131
5133042241143401
64502030242301
7522146431045
oct116427023635
930180782161
1010542131101
11451a838147
122062656391
13cc01040c8
14720164725
1541a799601
hex2745c279d

10542131101 has 2 divisors, whose sum is σ = 10542131102. Its totient is φ = 10542131100.

The previous prime is 10542131087. The next prime is 10542131111. The reversal of 10542131101 is 10113124501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6597663076 + 3944468025 = 81226^2 + 62805^2 .

It is a cyclic number.

It is not a de Polignac number, because 10542131101 - 223 = 10533742493 is a prime.

It is a super-2 number, since 2×105421311012 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10542131111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5271065550 + 5271065551.

It is an arithmetic number, because the mean of its divisors is an integer number (5271065551).

Almost surely, 210542131101 is an apocalyptic number.

It is an amenable number.

10542131101 is a deficient number, since it is larger than the sum of its proper divisors (1).

10542131101 is an equidigital number, since it uses as much as digits as its factorization.

10542131101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 10542131101 its reverse (10113124501), we get a palindrome (20655255602).

The spelling of 10542131101 in words is "ten billion, five hundred forty-two million, one hundred thirty-one thousand, one hundred one".