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1054331112049 is a prime number
BaseRepresentation
bin11110101011110110000…
…10000000101001110001
310201210102010222212220021
433111323002000221301
5114233232231041144
62124204130443441
7136113210404425
oct17257302005161
93653363885807
101054331112049
11377159476596
12150405433581
137856642bc57
143905c07cb85
151c65b488884
hexf57b080a71

1054331112049 has 2 divisors, whose sum is σ = 1054331112050. Its totient is φ = 1054331112048.

The previous prime is 1054331112017. The next prime is 1054331112137. The reversal of 1054331112049 is 9402111334501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1042808592400 + 11522519649 = 1021180^2 + 107343^2 .

It is a cyclic number.

It is not a de Polignac number, because 1054331112049 - 25 = 1054331112017 is a prime.

It is a super-2 number, since 2×10543311120492 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1054331113049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527165556024 + 527165556025.

It is an arithmetic number, because the mean of its divisors is an integer number (527165556025).

Almost surely, 21054331112049 is an apocalyptic number.

It is an amenable number.

1054331112049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1054331112049 is an equidigital number, since it uses as much as digits as its factorization.

1054331112049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 34.

The spelling of 1054331112049 in words is "one trillion, fifty-four billion, three hundred thirty-one million, one hundred twelve thousand, forty-nine".