1054331112137 has 2 divisors, whose sum is σ = 1054331112138. Its totient is φ = 1054331112136.

The previous prime is 1054331112049. The next prime is 1054331112143. The reversal of 1054331112137 is 7312111334501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 830465867401 + 223865244736 = 911299^2 + 473144^2 .

It is a cyclic number.

It is not a de Polignac number, because 1054331112137 - 2¹² = 1054331108041 is a prime.

It is a super-2 number, since 2×1054331112137² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1054331112157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527165556068 + 527165556069.

It is an arithmetic number, because the mean of its divisors is an integer number (527165556069).

Almost surely, 2^{1054331112137} is an apocalyptic number.

It is an amenable number.

1054331112137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1054331112137 is an equidigital number, since it uses as much as digits as its factorization.

1054331112137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7560, while the sum is 32.

Adding to 1054331112137 its reverse (7312111334501), we get a palindrome (8366442446638).

The spelling of 1054331112137 in words is "one trillion, fifty-four billion, three hundred thirty-one million, one hundred twelve thousand, one hundred thirty-seven".