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1054444413047 is a prime number
BaseRepresentation
bin11110101100000011100…
…10001110000001110111
310201210201001012011122112
433112001302032001313
5114234000232204142
62124223255121235
7136116054425144
oct17260162160167
93653631164575
101054444413047
11377207422283
1215043737321b
1378583a4b96c
143906d1333cb
151c6663b9382
hexf581c8e077

1054444413047 has 2 divisors, whose sum is σ = 1054444413048. Its totient is φ = 1054444413046.

The previous prime is 1054444412981. The next prime is 1054444413059. The reversal of 1054444413047 is 7403144444501.

1054444413047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1054444413047 is a prime.

It is a super-2 number, since 2×10544444130472 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1054444412995 and 1054444413013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1054444413947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527222206523 + 527222206524.

It is an arithmetic number, because the mean of its divisors is an integer number (527222206524).

Almost surely, 21054444413047 is an apocalyptic number.

1054444413047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1054444413047 is an equidigital number, since it uses as much as digits as its factorization.

1054444413047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 430080, while the sum is 41.

Adding to 1054444413047 its reverse (7403144444501), we get a palindrome (8457588857548).

The spelling of 1054444413047 in words is "one trillion, fifty-four billion, four hundred forty-four million, four hundred thirteen thousand, forty-seven".