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10548913194293 is a prime number
BaseRepresentation
bin1001100110000001110000…
…1110010100010100110101
31101100110120220020200112112
42121200130032110110311
52340313133234204133
634234034231500405
72136063621455645
oct231403416242465
941313526220475
1010548913194293
1133a7850541331
121224549827705
135b69b1b34ac6
142867da5ba525
15134604cde648
hex9981c394535

10548913194293 has 2 divisors, whose sum is σ = 10548913194294. Its totient is φ = 10548913194292.

The previous prime is 10548913194217. The next prime is 10548913194331. The reversal of 10548913194293 is 39249131984501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9902614572964 + 646298621329 = 3146842^2 + 803927^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10548913194293 is a prime.

It is a super-2 number, since 2×105489131942932 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10548913194893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5274456597146 + 5274456597147.

It is an arithmetic number, because the mean of its divisors is an integer number (5274456597147).

Almost surely, 210548913194293 is an apocalyptic number.

It is an amenable number.

10548913194293 is a deficient number, since it is larger than the sum of its proper divisors (1).

10548913194293 is an equidigital number, since it uses as much as digits as its factorization.

10548913194293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8398080, while the sum is 59.

The spelling of 10548913194293 in words is "ten trillion, five hundred forty-eight billion, nine hundred thirteen million, one hundred ninety-four thousand, two hundred ninety-three".