Base | Representation |
---|---|
bin | 11110101101001010111… |
… | …01101100100110001001 |
3 | 10201212020202120012102012 |
4 | 33112211131230212021 |
5 | 114241212002404001 |
6 | 2124402521145305 |
7 | 136136643433415 |
oct | 17264535544611 |
9 | 3655222505365 |
10 | 1055043013001 |
11 | 37749430428a |
12 | 15058392b235 |
13 | 7864aa77213 |
14 | 390c8833d45 |
15 | 1c69dc0c2bb |
hex | f5a576c989 |
1055043013001 has 2 divisors, whose sum is σ = 1055043013002. Its totient is φ = 1055043013000.
The previous prime is 1055043012937. The next prime is 1055043013009. The reversal of 1055043013001 is 1003103405501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1033485726025 + 21557286976 = 1016605^2 + 146824^2 .
It is a cyclic number.
It is not a de Polignac number, because 1055043013001 - 26 = 1055043012937 is a prime.
It is a super-2 number, since 2×10550430130012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1055043013009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527521506500 + 527521506501.
It is an arithmetic number, because the mean of its divisors is an integer number (527521506501).
Almost surely, 21055043013001 is an apocalyptic number.
It is an amenable number.
1055043013001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1055043013001 is an equidigital number, since it uses as much as digits as its factorization.
1055043013001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 1055043013001 its reverse (1003103405501), we get a palindrome (2058146418502).
The spelling of 1055043013001 in words is "one trillion, fifty-five billion, forty-three million, thirteen thousand, one".
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