1055100113 has 4 divisors (see below), whose sum is σ = 1056136560. Its totient is φ = 1054063668.

The previous prime is 1055100107. The next prime is 1055100119. The reversal of 1055100113 is 3110015501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1055100107) and next prime (1055100119).

It is a cyclic number.

It is not a de Polignac number, because 1055100113 - 2⁶ = 1055100049 is a prime.

It is a super-2 number, since 2×1055100113² = 2226472496905225538, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1055100091 and 1055100100.

It is not an unprimeable number, because it can be changed into a prime (1055100119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 516695 + ... + 518732.

It is an arithmetic number, because the mean of its divisors is an integer number (264034140).

Almost surely, 2^1055100113 is an apocalyptic number.

It is an amenable number.

1055100113 is a deficient number, since it is larger than the sum of its proper divisors (1036447).

1055100113 is a wasteful number, since it uses less digits than its factorization.

1055100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1036446.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 1055100113 is about 32482.3046134353. The cubic root of 1055100113 is about 1018.0393301309.

Adding to 1055100113 its reverse (3110015501), we get a palindrome (4165115614).

The spelling of 1055100113 in words is "one billion, fifty-five million, one hundred thousand, one hundred thirteen".