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1055125553401 is a prime number
BaseRepresentation
bin11110101101010100110…
…00100100000011111001
310201212110111212200120001
433112222120210003321
5114241344120202101
62124415030233001
7136141665140113
oct17265230440371
93655414780501
101055125553401
11377526960097
121505a74b5761
1378661bb69aa
14390d579c3b3
151c6a60b3901
hexf5aa6240f9

1055125553401 has 2 divisors, whose sum is σ = 1055125553402. Its totient is φ = 1055125553400.

The previous prime is 1055125553399. The next prime is 1055125553411. The reversal of 1055125553401 is 1043555215501.

1055125553401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1015822094400 + 39303459001 = 1007880^2 + 198251^2 .

It is a cyclic number.

It is not a de Polignac number, because 1055125553401 - 21 = 1055125553399 is a prime.

It is a super-2 number, since 2×10551255534012 (a number of 25 digits) contains 22 as substring.

Together with 1055125553399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1055125553411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527562776700 + 527562776701.

It is an arithmetic number, because the mean of its divisors is an integer number (527562776701).

Almost surely, 21055125553401 is an apocalyptic number.

It is an amenable number.

1055125553401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1055125553401 is an equidigital number, since it uses as much as digits as its factorization.

1055125553401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75000, while the sum is 37.

The spelling of 1055125553401 in words is "one trillion, fifty-five billion, one hundred twenty-five million, five hundred fifty-three thousand, four hundred one".