Base | Representation |
---|---|
bin | 11110101101101011001… |
… | …01010110001010000111 |
3 | 10201212221121110000022111 |
4 | 33112311211112022013 |
5 | 114242240221004303 |
6 | 2124445421441451 |
7 | 136146436231315 |
oct | 17266545261207 |
9 | 3655847400274 |
10 | 1055313453703 |
11 | 377612a293a3 |
12 | 15063a410287 |
13 | 78691ac57c2 |
14 | 391127110b5 |
15 | 1c6b782cb6d |
hex | f5b5956287 |
1055313453703 has 2 divisors, whose sum is σ = 1055313453704. Its totient is φ = 1055313453702.
The previous prime is 1055313453679. The next prime is 1055313453709. The reversal of 1055313453703 is 3073543135501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1055313453703 - 221 = 1055311356551 is a prime.
It is a super-2 number, since 2×10553134537032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1055313453709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527656726851 + 527656726852.
It is an arithmetic number, because the mean of its divisors is an integer number (527656726852).
Almost surely, 21055313453703 is an apocalyptic number.
1055313453703 is a deficient number, since it is larger than the sum of its proper divisors (1).
1055313453703 is an equidigital number, since it uses as much as digits as its factorization.
1055313453703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 283500, while the sum is 40.
The spelling of 1055313453703 in words is "one trillion, fifty-five billion, three hundred thirteen million, four hundred fifty-three thousand, seven hundred three".
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