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1055315122181 is a prime number
BaseRepresentation
bin11110101101101011010…
…11101101100000000101
310201212221201120210000222
433112311223231200011
5114242241132402211
62124445521314125
7136146456350555
oct17266553554005
93655851523028
101055315122181
11377613968a01
1215063aa95945
137869225b078
1439112a27165
151c6b7a5c1db
hexf5b5aed805

1055315122181 has 2 divisors, whose sum is σ = 1055315122182. Its totient is φ = 1055315122180.

The previous prime is 1055315122151. The next prime is 1055315122237. The reversal of 1055315122181 is 1812215135501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1049917869025 + 5397253156 = 1024655^2 + 73466^2 .

It is an emirp because it is prime and its reverse (1812215135501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1055315122181 - 226 = 1055248013317 is a prime.

It is a super-2 number, since 2×10553151221812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1055315122111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527657561090 + 527657561091.

It is an arithmetic number, because the mean of its divisors is an integer number (527657561091).

Almost surely, 21055315122181 is an apocalyptic number.

It is an amenable number.

1055315122181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1055315122181 is an equidigital number, since it uses as much as digits as its factorization.

1055315122181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 35.

The spelling of 1055315122181 in words is "one trillion, fifty-five billion, three hundred fifteen million, one hundred twenty-two thousand, one hundred eighty-one".