Base | Representation |
---|---|
bin | 1001100110010010011111… |
… | …0010110000111101010111 |
3 | 1101100220011202020010110112 |
4 | 2121210213302300331113 |
5 | 2340401331434443211 |
6 | 34240055512113235 |
7 | 2136313101110624 |
oct | 231444762607527 |
9 | 41326152203415 |
10 | 10553402265431 |
11 | 33a97444a7983 |
12 | 12253a109581b |
13 | 5b7248b8300c |
14 | 286b0487d34b |
15 | 1347b8e6e88b |
hex | 99927cb0f57 |
10553402265431 has 2 divisors, whose sum is σ = 10553402265432. Its totient is φ = 10553402265430.
The previous prime is 10553402265409. The next prime is 10553402265499. The reversal of 10553402265431 is 13456220435501.
It is a weak prime.
It is an emirp because it is prime and its reverse (13456220435501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10553402265431 - 210 = 10553402264407 is a prime.
It is a super-3 number, since 3×105534022654313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10553402265031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5276701132715 + 5276701132716.
It is an arithmetic number, because the mean of its divisors is an integer number (5276701132716).
Almost surely, 210553402265431 is an apocalyptic number.
10553402265431 is a deficient number, since it is larger than the sum of its proper divisors (1).
10553402265431 is an equidigital number, since it uses as much as digits as its factorization.
10553402265431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 41.
The spelling of 10553402265431 in words is "ten trillion, five hundred fifty-three billion, four hundred two million, two hundred sixty-five thousand, four hundred thirty-one".
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