Base | Representation |
---|---|
bin | 11110101110100011010… |
… | …00010010010000011111 |
3 | 10201221011101211112120021 |
4 | 33113101220102100133 |
5 | 114244221200024312 |
6 | 2125004230533011 |
7 | 136164211545226 |
oct | 17272150222037 |
9 | 3657141745507 |
10 | 1055783986207 |
11 | 377834599435 |
12 | 15074bb07167 |
13 | 787384310c2 |
14 | 39158dd5cbd |
15 | 1c6e3cc4c07 |
hex | f5d1a1241f |
1055783986207 has 2 divisors, whose sum is σ = 1055783986208. Its totient is φ = 1055783986206.
The previous prime is 1055783986129. The next prime is 1055783986211. The reversal of 1055783986207 is 7026893875501.
1055783986207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1055783986207 - 27 = 1055783986079 is a prime.
It is a super-3 number, since 3×10557839862073 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1055783986297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527891993103 + 527891993104.
It is an arithmetic number, because the mean of its divisors is an integer number (527891993104).
Almost surely, 21055783986207 is an apocalyptic number.
1055783986207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1055783986207 is an equidigital number, since it uses as much as digits as its factorization.
1055783986207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25401600, while the sum is 61.
The spelling of 1055783986207 in words is "one trillion, fifty-five billion, seven hundred eighty-three million, nine hundred eighty-six thousand, two hundred seven".
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