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1056094433 is a prime number
BaseRepresentation
bin111110111100101…
…011100011100001
32201121020011012122
4332330223203201
54130330010213
6252443434025
735112440342
oct7674534341
92647204178
101056094433
114a2157419
12255825915
1313aa4a564
14a03900c9
1562ab1d08
hex3ef2b8e1

1056094433 has 2 divisors, whose sum is σ = 1056094434. Its totient is φ = 1056094432.

The previous prime is 1056094373. The next prime is 1056094439. The reversal of 1056094433 is 3344906501.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 848964769 + 207129664 = 29137^2 + 14392^2 .

It is a cyclic number.

It is not a de Polignac number, because 1056094433 - 218 = 1055832289 is a prime.

It is a super-2 number, since 2×10560944332 = 2230670902827182978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1056094393 and 1056094402.

It is not a weakly prime, because it can be changed into another prime (1056094439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528047216 + 528047217.

It is an arithmetic number, because the mean of its divisors is an integer number (528047217).

Almost surely, 21056094433 is an apocalyptic number.

It is an amenable number.

1056094433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1056094433 is an equidigital number, since it uses as much as digits as its factorization.

1056094433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 35.

The square root of 1056094433 is about 32497.6065734078. The cubic root of 1056094433 is about 1018.3590277720.

The spelling of 1056094433 in words is "one billion, fifty-six million, ninety-four thousand, four hundred thirty-three".