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105874943 is a prime number
BaseRepresentation
bin1100100111110…
…00010111111111
321101020000010012
412103320113333
5204100444233
614301133435
72423631206
oct623702777
9241200105
10105874943
1154844459
122b55a27b
1318c1c8c5
14100c023d
159465548
hex64f85ff

105874943 has 2 divisors, whose sum is σ = 105874944. Its totient is φ = 105874942.

The previous prime is 105874939. The next prime is 105875041. The reversal of 105874943 is 349478501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 105874943 - 22 = 105874939 is a prime.

It is a super-2 number, since 2×1058749432 = 22419007110506498, which contains 22 as substring.

It is an alternating number because its digits alternate between odd and even.

It is a self number, because there is not a number n which added to its sum of digits gives 105874943.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105874913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52937471 + 52937472.

It is an arithmetic number, because the mean of its divisors is an integer number (52937472).

Almost surely, 2105874943 is an apocalyptic number.

105874943 is a deficient number, since it is larger than the sum of its proper divisors (1).

105874943 is an equidigital number, since it uses as much as digits as its factorization.

105874943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 41.

The square root of 105874943 is about 10289.5550438296. Note that the first 3 decimals coincide. The cubic root of 105874943 is about 473.0761602487.

The spelling of 105874943 in words is "one hundred five million, eight hundred seventy-four thousand, nine hundred forty-three".