1059363408813 has 4 divisors (see below), whose sum is σ = 1412484545088. Its totient is φ = 706242272540.

The previous prime is 1059363408811. The next prime is 1059363408821. The reversal of 1059363408813 is 3188043639501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1059363408813 - 2¹ = 1059363408811 is a prime.

It is a super-2 number, since 2×1059363408813² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1059363408811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176560568133 + ... + 176560568138.

It is an arithmetic number, because the mean of its divisors is an integer number (353121136272).

Almost surely, 2^{1059363408813} is an apocalyptic number.

It is an amenable number.

1059363408813 is a deficient number, since it is larger than the sum of its proper divisors (353121136275).

1059363408813 is an equidigital number, since it uses as much as digits as its factorization.

1059363408813 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 353121136274.

The product of its (nonzero) digits is 1866240, while the sum is 51.

The spelling of 1059363408813 in words is "one trillion, fifty-nine billion, three hundred sixty-three million, four hundred eight thousand, eight hundred thirteen".