10597131355931 has 4 divisors (see below), whose sum is σ = 10597281636000. Its totient is φ = 10596981075864.

The previous prime is 10597131355913. The next prime is 10597131355957. The reversal of 10597131355931 is 13955313179501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10597131355931 is a prime.

It is a super-4 number, since 4×10597131355931⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10597131355901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75034211 + ... + 75175308.

It is an arithmetic number, because the mean of its divisors is an integer number (2649320409000).

Almost surely, 2^{10597131355931} is an apocalyptic number.

10597131355931 is a deficient number, since it is larger than the sum of its proper divisors (150280069).

10597131355931 is an equidigital number, since it uses as much as digits as its factorization.

10597131355931 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 150280068.

The product of its (nonzero) digits is 1913625, while the sum is 53.

The spelling of 10597131355931 in words is "ten trillion, five hundred ninety-seven billion, one hundred thirty-one million, three hundred fifty-five thousand, nine hundred thirty-one".