Base | Representation |
---|---|
bin | 1100101000101… |
… | …01010110110101 |
3 | 21101110000221212 |
4 | 12110111112311 |
5 | 204113244103 |
6 | 14303451205 |
7 | 2424634253 |
oct | 624252665 |
9 | 241400855 |
10 | 105993653 |
11 | 54915667 |
12 | 2b5b6b05 |
13 | 18c6194c |
14 | 101115d3 |
15 | 948a7d8 |
hex | 65155b5 |
105993653 has 2 divisors, whose sum is σ = 105993654. Its totient is φ = 105993652.
The previous prime is 105993631. The next prime is 105993659. The reversal of 105993653 is 356399501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 61811044 + 44182609 = 7862^2 + 6647^2 .
It is a cyclic number.
It is not a de Polignac number, because 105993653 - 210 = 105992629 is a prime.
It is a super-2 number, since 2×1059936532 = 22469308952568818, which contains 22 as substring.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 105993653.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105993659) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52996826 + 52996827.
It is an arithmetic number, because the mean of its divisors is an integer number (52996827).
Almost surely, 2105993653 is an apocalyptic number.
It is an amenable number.
105993653 is a deficient number, since it is larger than the sum of its proper divisors (1).
105993653 is an equidigital number, since it uses as much as digits as its factorization.
105993653 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 109350, while the sum is 41.
The square root of 105993653 is about 10295.3218988043. The cubic root of 105993653 is about 473.2529030280.
The spelling of 105993653 in words is "one hundred five million, nine hundred ninety-three thousand, six hundred fifty-three".
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