Base | Representation |
---|---|
bin | 11000001000000100001010… |
… | …100001010001011101100111 |
3 | 111220200202121012200000102002 |
4 | 120020010022201101131213 |
5 | 102401430314421321434 |
6 | 1013401012442235515 |
7 | 31231000613540633 |
oct | 3010041241213547 |
9 | 456622535600362 |
10 | 106107343542119 |
11 | 308999652425a7 |
12 | ba983927b5b9b |
13 | 4728b5852306a |
14 | 1c2b8a1087dc3 |
15 | c4016751b57e |
hex | 60810a851767 |
106107343542119 has 2 divisors, whose sum is σ = 106107343542120. Its totient is φ = 106107343542118.
The previous prime is 106107343542113. The next prime is 106107343542157. The reversal of 106107343542119 is 911245343701601.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 106107343542119 - 236 = 106038624065383 is a prime.
It is a super-3 number, since 3×1061073435421193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (106107343542113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53053671771059 + 53053671771060.
It is an arithmetic number, because the mean of its divisors is an integer number (53053671771060).
Almost surely, 2106107343542119 is an apocalyptic number.
106107343542119 is a deficient number, since it is larger than the sum of its proper divisors (1).
106107343542119 is an equidigital number, since it uses as much as digits as its factorization.
106107343542119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 47.
The spelling of 106107343542119 in words is "one hundred six trillion, one hundred seven billion, three hundred forty-three million, five hundred forty-two thousand, one hundred nineteen".
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