Search a number
-
+
10680473471 = 25219423509
BaseRepresentation
bin10011111001001101…
…10001011101111111
31000120100012021020112
421330212301131333
5133333200122341
64523451340235
7525446345423
oct117446613577
930510167215
1010680473471
114590937888
1220a0a5167b
131012980ab5
14734696b83
154279c4aeb
hex27c9b177f

10680473471 has 4 divisors (see below), whose sum is σ = 10680922200. Its totient is φ = 10680024744.

The previous prime is 10680473467. The next prime is 10680473497. The reversal of 10680473471 is 17437408601.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10680473471 - 22 = 10680473467 is a prime.

It is a super-3 number, since 3×106804734713 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10680403471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186536 + ... + 236973.

It is an arithmetic number, because the mean of its divisors is an integer number (2670230550).

Almost surely, 210680473471 is an apocalyptic number.

10680473471 is a deficient number, since it is larger than the sum of its proper divisors (448729).

10680473471 is an equidigital number, since it uses as much as digits as its factorization.

10680473471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448728.

The product of its (nonzero) digits is 112896, while the sum is 41.

The spelling of 10680473471 in words is "ten billion, six hundred eighty million, four hundred seventy-three thousand, four hundred seventy-one".

Divisors: 1 25219 423509 10680473471