Base | Representation |
---|---|
bin | 110010110100001100… |
… | …0100010111000001101 |
3 | 101102200010210002102221 |
4 | 1211220120202320031 |
5 | 3241442103302211 |
6 | 122044225015341 |
7 | 10612141665532 |
oct | 1455030427015 |
9 | 342603702387 |
10 | 109125447181 |
11 | 42309519693 |
12 | 19195a84551 |
13 | a3a127312a |
14 | 53d2dacd89 |
15 | 2c8a445c71 |
hex | 1968622e0d |
109125447181 has 2 divisors, whose sum is σ = 109125447182. Its totient is φ = 109125447180.
The previous prime is 109125447143. The next prime is 109125447271. The reversal of 109125447181 is 181744521901.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107496113956 + 1629333225 = 327866^2 + 40365^2 .
It is a cyclic number.
It is not a de Polignac number, because 109125447181 - 235 = 74765708813 is a prime.
It is a super-2 number, since 2×1091254471812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (109125447121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54562723590 + 54562723591.
It is an arithmetic number, because the mean of its divisors is an integer number (54562723591).
Almost surely, 2109125447181 is an apocalyptic number.
It is an amenable number.
109125447181 is a deficient number, since it is larger than the sum of its proper divisors (1).
109125447181 is an equidigital number, since it uses as much as digits as its factorization.
109125447181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 43.
The spelling of 109125447181 in words is "one hundred nine billion, one hundred twenty-five million, four hundred forty-seven thousand, one hundred eighty-one".
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